Logan wants to mix an 18% acid solution with a 45% acid solution to get 16l of a 36% acid solution. how many liters of the 18% solution and how many liters of the 45% solution should be mixed?

Logan needs 5⅓ liters of 18% acid and 10⅔ liters of 45% acid.

Step-by-step explanation:

If x is the liters of 18% acid, and y is the liters of 45% acid, then:

x + y = 16

0.18x + 0.45y = 0.36(16)

Solve the system of equations.  Using substitution:

0.18x + 0.45(16 − x) = 0.36(16)

0.18x + 7.2 − 0.45x = 5.76

1.44 = 0.27x

x = 5⅓

y = 16 − x

y = 10⅔

Logan needs 5⅓ liters of 18% acid and 10⅔ liters of 45% acid.

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hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)