(6,-2); y=-3x+4 write an equation of the line that passes through the given point andbis perpendicular to the grapg of the given equation

y=1/3x-4

Step-by-step explanation:

y-y1=m(x-x1)

the perpendicular slope is  1/3 so y+2=1/3(x-6)

y+2=1/3x-2

y=1/3x-4

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: