Can someone answer this math question

The second missile will destroy first missile at hieght of 64.76m above the ground at time 19.15475 seconds

Step-by-step explanation:

Step-by-step explanation:

The military is performing missile test,

The one missile is launched from the ground and its path is modeled by the equation as : y= f(x) =

After 10 seconds, Second heat-seeking missile is launched and its path is modeled by the equation as : y= g(x) =

After 10 seconds, first missile will be at height of f(10)

f(10) =

f(10) =  

When both the missile collide each other at same hieght of y

Also. If x is time for f(x) then, time for g(x) will be x-10 such that Second heat-seeking missile is launched after 10 second of  first missile is launched

At time of collision, f(x)=g(x-10)

Roots of x are 19.15475  and -39.1547

Negative time is not possible

Therefore, time at x=19.15475 seconds

And both missiles collide as y=f(19.15475 ) or g(19.15475 -10)

f(x) =

f(19.15475) =

f(19.15475) = 64.76m above the ground.

Thus, The second missile will destroy first missile at hieght of 64.76m above the ground at time 19.15475 seconds

ome people is not even worth it to even try it in the air.

step-by-step explanation:

you can use a^2+ b^2=c^2