Atriangle has side lengths of 7 in., 9 in., and 11.
determine whether this is a right triangle and why

no

Step-by-step explanation:

because when you Multiply 7 to the power of 2 its automatically greater than the actual answer and obviously the 9 to the power of 2 already is a lot greater than 11 times 11.

It is not a right triangle because the other side is 11 and not 11.40  when we apply the Pythagoras theorem rule on it

Step-by-step explanation:

To determine whether it is a right triangle, all we simply need to do is to check using the Pythagoras theorem formula, Using the Pythagoras theorm formula;

opposite² + adjacent² = hypotenuse²

let opposite  = 7 and let adjacent = 9   let the hypotenuse be x, if we calculate and x gives 11 then we will know it is a right-triangle

7² + 9² = x²

49 + 81 = x²

130 = x²

Take the square root of both-side

√130 =√ x²

11.40 = x

Therefore it is not a right triangle because the other side is 11 and not 11.40  when we apply the Pythagoras theorem rule on it

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2