Mathematics, 07.12.2019 06:31 leahmitch612

Trying to make honor roll <me out

which equation has exactly one solution

a. n - 2n + 1 = 2n - 3n - 1
b. 2n - n = 2n - 3n
c. 1 - n - 2n = 1 - 2n - n
d. n - (1 - 2n) = 2n + (n - 1)

Answers: 1

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Trying to make honor roll <me out

which equation has exactly one solution

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Trying to make honor roll <me out which equation has exactly one solution a. n - 2n + 1 = 2n - 3n - 1 b. 2n - n = 2n - 3n c. 1 - n - 2n = 1 - 2n - n d. n - (1 - 2n) = 2n + (n - 1)

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Another question on Mathematics

Trying to make honor roll <me out

which equation has exactly one solution

a. n - 2n + 1 = 2n - 3n - 1
b. 2n - n = 2n - 3n
c. 1 - n - 2n = 1 - 2n - n
d. n - (1 - 2n) = 2n + (n - 1)