Asound wave is given the following equation:

y= 8 sin(512πt) where t= time in seconds.

how many cycles will occur between t=2 and t=3.5 seconds?

384

Step-by-step explanation:

Standard equation of a sine wave is:

y = A sin(2πf x + B) + C

where A is the amplitude, f is the frequency, B is the phase shift, and C is the vertical offset.

In this case:

2πf = 512π

f = 256

This means there are 256 cycles per second.  The number of cycles between t = 2 and t = 3.5 is:

(3.5 − 2) × 256

384

900 degrees

step-by-step explanation:

answer: 270

step-by-step explanation:

you have to times 200 by 1.35 to get your answer