Atriangle has side lengths 6, 7, and b, and the angle between the sides of lengths 6 and 7 measures 60 degress. if a si the area of the triangle and b is the integer closet b, find the value of a/b.

Step-by-step explanation:

We have cosine formula

           c² = a² + b² - 2ab cosC

Here

          c = B

          a = 6

          b = 7

          C = 60°

Substituting

          B² = 6² + 7² - 2 x 6 x 7 cos60

          B² = 43

          B = 6.56

           b = 7 closest integer to B.

Given that A is area of triangle

          A=0.5absinC

          A = 0.5 x 6 x 7 x sin60 = 18.19

We need to find

The value of A/b is 2.60      

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.