Identify an equation in slope-intercept form for the line parallel to y = 5x + 2
that passes through (-6, -1).
а. y= 5х - 29
-5x - 11

d. у= 5х + 29
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D. y = 5x + 29

Step-by-step explanation:

To write an equation of a line in slope-intercept form, we need to find the slope and the y-intercept.

The equation of a line is y=mx + b.

x and y are the coordinates of any point on a line.

m is the slope.

b is the y-intercept.

Lines are parallel to each other when they have the same slope. A line parallel to y = 5x + 2 would also have the slope 5.

m = 5

Since we have a point on the line, (-6, -1) and the slope, 5, there is only one missing variable, b, the y-intercept.

Substitute the known information into the equation and isolate b.

y = mx + b

-1 = 5(-6) + b  <=Simplify by solving 5 X -6

-1 = -30 + b

-1 + 30 = -30 + 30 + b  <= Add 30 to both sides to isolate b

29 = b

b = 29  <= Standard formatting puts the variable on the left side

Put the m and b values into the equation of a line to solve:

y = mx + b

y = 5x + 29

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question: match the eqaution with its graph -8x - 5y = 40

answer: 8 x 5 = 40

x= absiss

y= orderly

so you have a proportional graph

question answered by

(jacemorris04)