20 different comic books will be distributed to five kids. (a) how many ways are there to distribute the comic books if there are no restrictions on how many go to each kid (other than the fact that all 20 will be given out)?

9.53674E+13

Step-by-step explanation:

given that 20 different comic books will be distributed to five kids.

Also given that there are no restrictions on how many go to each kid (other than the fact that all 20 will be given out)

Hence each kid can get any number of books and there is no chance a kid does not get any book also.

There are 5 kids.

Take the first book.  It can be given to any one of the 5 kids in 5 ways

Now second book can be similarly given to any one of the 5 kids in 5 ways

this continues for all 20 books

Total no of ways =

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

answer: i guess 105 degrees?

step-by-step explanation: