Which is true given the two equations below?

3 + 2 = 5
3 - 2 = 1
a.
(3, 2) is the intersection point of the graphs of
3x + 2y = 5 and 3x - 2y = 1.

b.
(3, 2) is the intersection point of the graphs of
x + y = 5 and x - y = 1.

c.
(5, 1) is the intersection point of the graphs of
3x + 2y = 5 and 3x - 2y = 1.

d.
(5, 1) is the intersection point of the graphs of
x + y = 5 and x - y = 1.

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15