17. write the equation of a line that is perpendicular to the given line and that passes through the
given point.
» _ 3 = 8(4 + 2); (-2, 3)
(1 point)
oy +3 = -2(x - 2)
oy -3 ==« +2)
oy-2 =(x+3)

Option 2

The equation of a line that is perpendicular to the given line and that passes through the  given point (-2, 3) is

Given that line that is perpendicular to the given line and that passes through the  given point (-2, 3)

We have to find the equation of line

The point slope form is given as:

Where "m" is the slope of line

Comparing the given equation with point slope form

Thus slope of line is

We know that product of slopes of perpendicular lines are always equal to -1

Slope of given line x slope of line perpendicular to given line = -1

Now we have to find the equation of line having slope and passes through point (-2, 3)

Thus the required equation is found and option 2 is correct

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents