Find the area of a trapezium whose parallel sides 25cm, 13cm and other sides are 15cm
and 15cm.

The area of Trapezium is 171 cm² .

Step-by-step explanation:

Given as for a trapezium :

The measure of parallel sides are 25 cm and 13 cm

I.e AB = 25 cm  , CD = 13 cm

The measure of other sides of the trapezium = AD = BC = 15 cm

Let The height of measure h is drawn on the side AB

So , The BOC is now a triangle

∴ The measure of BO = AB - AO = 25 cm - 13 cm = 12 cm

Let the area of Trapezium = A

Now, height h =

Or, h =  

Or, h =  

∴  h =  

I.e h = 9 cm

From figure

∵ Area of trapezium = ×Height×( sum of parallel side )

or, A = ×h×( AB + CD )

or , A =  ×9×( 25 + 13 )

Or, A = ×9×38

∴ Area = 171 cm²

Hence The area of Trapezium is 171 cm² . Answer

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.

2

step-by-step explanation: