Joshua traveled 5 hours from city a to city b. the distance between the cities is 260 miles. first he traveled at the constant speed of 40 mi/h, and then at the constant speed of 60 mi/h. how many hours did he travel at the constant speed of 60 mi/h?

Joshua  travelled for 3 hours at the constant speed of 60 mi/h

Given that, Joshua traveled 5 hours from City A to City B

The distance between the cities is 260 miles.  

First he traveled at the constant speed of 40 mi/h, and then at the constant speed of 60 mi/h.  

So, let the number of hours he travelled with 40 mi/h be "n" hours and the distance travelled be "x" miles

Then, the time in which he travelled with 60 mi/h will be 5 – n hours and distance travelled will be 260 – x miles

We have to find how many hours did he travel at the constant speed of 60 mi/h

The relation between speed and distance is given as:

So, he travelled 2 hours with speed of 40 mi/h and 5 – 2 = 3 hours with speed of 60 mi/h

Hence, he travelled for 3 hours

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )

answer: howdy

step-by-step explanation: