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a rectangular pool is surrounded by a walk 2 meters wide. the pool is 3 meters longer than its width. if the total area of the pool and walk is 188 square meters more than the area of the pool, find the dimensions of the pool.

width=20m,length=23m

Step-by-step explanation:

as shown in the figure which is attached

let width of pool =x

⇒ length of pool=x+3

width of walk =2

⇒width of outer boundary of walk=x+4 (2 on each side of pool)

   length of outer boundary of walk=x+3+4=x+7

area of pool =x×(x+3)

area of walk+pool=(x+4)×(x+7)

given

total area of the pool and walk is 188 square meters more than the area of the pool

⇒(x+4)×(x+7)=188+x×(x+3)

⇒8x=160

x=20m

dimensions of pool

widh=20m

length=20+3=23m

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq