There are 20 members of a basketball team.

(a) the coach must select 12 players to travel to an away game. how many ways are there to select the players who will travel?

(b) from the 12 players who will travel, the coach must select her starting line-up. she will select a player for each of the five positions: center, right forward, left forward, right guard, left guard. how many ways are there for her to select the starting line-up?

(c) from the 12 players who will travel, the coach must select her starting line-up. she will select a player for each of the five positions: center, right forward, left forward, right guard, left guard. however, there are only three of the 12 players who can play center. otherwise, there are no restrictions. how many ways are there for her to select the starting line-up?

a)125970

b)95040

c)35640

Step-by-step explanation:

a) selecting 12 player from 20 players can be one in

  =

          =  

          =

b) since each position has an identity permutations can be used so

   Number of ways =

                                =

                                =

                                =

c) coach permutes 4 players for position other than centers in   ways and selects center in 3 ways

  so, number of ways =

                                     =

                                     =

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

happy to

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