Alocal sorority sold hot dogs and bratwursts at the spring fling picnics. the first day they sold 8 dozen hot dogs and 13 dozen bratwursts for $282.60. the second day they sold 10 dozen hot dogs and 15 dozen bratwursts for a total of $333.00. how much did each cost? solve this system using an inverse matrix. (hint: it's easier to leave the dozens in the problem until the last step.)

1 hot dog costs $0.75

1 bratwurst costs $1.35

Step-by-step explanation:

Let x and y be the price per dozen of hot dogs and bratwursts respectively.

The first day they sold 8 dozen hot dogs and 13 dozen bratwursts for $282.60

8x + 13y = 282.60

The second day they sold 10 dozen hot dogs and 15 dozen bratwursts for a total of $333.00

10x + 15y = 333

and we have the linear system

8x + 13y = 282.60

10x + 15y = 333

which can be written in matrix form as

The solution would be given by

We have  

hence

Now,

if a dozen hot dogs cost $9, 1 hot dog costs 9/12 = $0.75

if a dozen bratwursts cost $16.2, 1 bratwurst costs 16.2/12 = $1.35

168

step-by-step explanation:

i am pretty sure that the answer is 168

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a