How many ways are there to order the evaluation of the product of n matrices: m 1 m 2 . . m n ? for example, with two matrices, we have (m 1 m 2 )m 3 and m 1 (m 2 m3).

n-1 ways

Step-by-step explanation:

since there are 2 ways to order 3 matrices:

and

you can do it the same way for 4 matrices and notice a pattern:

the pattern here is that the number of ways to order the evaluation of multiplying matrices is 1 less than the number of matrices.

for matrices the order is

hope this helps!

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,

600,000,000,000, or 6e14

step-by-step explanation: