Adrop set of 20 gtt/ml is used to run a liter of fluid at 50 gtt/min. how long will it take for the liter to run out?

400 Minutes

Step-by-step explanation: 20 gtt/mL ÷ 50 gtt/min

⇒ 20/50 (gtt/gtt)(min/mL)

= 2/5 min/mL.

For a liter to run out it will take

⇒ 2/5 × 1000 = 400 minutes

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)