Visitors to a carnival can buy an unlimited-ride pass for $50 or an entrance-only pass for $20. in one day, 282 passes were sold for a total of $10,680. how many unlimited-ride passes were sold?

Number of Unlimited passes sold were 168.

Step-by-step explanation:

Let Number of Unlimited passes sold be x

and Number of entrance-only passes sold be y.

Total number of passes sold =282

Hence,

Also

Cost for unlimited-ride pass = $50

Cost for entrance-only pass = $20

Total Money for one day = $10,680

Hence,

Dividing by 10 on both side we get;

Now multiplying equation 1 by 2 we get;

Now Subtracting equation 3 from equation 2 we get;

x= 168

x+y = 282

168+y =282

y=282-168

y= 114

Hence, Number of Unlimited passes sold are 168 and Number of entrance-only pass sold is 114.

part a: triangles gcb and epb

part b. sides cg and rp are parallel by definition of parallelogram.

angles cgb and e are congruent by being alternate interior angles of parallel lines cut by a transversal. angles gbc and ebp are congruent because they are vertical angles. by aa similarity, the triangles are similar.

part c. since the triangles are similar, the ratios of the lengths of corresponding sides are equal.

calculation of be:

gb/be = cb/bp

(400 ft)/be = 300/200

(400 ft)/be = 3/2

3be = 2 * 400 ft

3be = 800 ft

be = 800/3 ft

calculation of pe:

gc/pe = cb/bp

(350 ft)/pe = 300/200

(350 ft)/pe = 3/2

3pe = 2 * 350 ft

3pe = 700 ft

pe = 700/3 ft