Arectangular pool has an area of 192 square feet. the length of the pool is 15 feet. what is the pools width rounded to the nearest foot?

in two or more complete sentences write and solve an equation for the solution and explain how you will solve the equation.

to find the width divide the area by the length.

width = 192 / 15 = 12.8

rounded to the nearest foot = 13 feet.

go on the tube you might find some information there

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?