Construct the perpendicular bisectors of each side of the triangle. extend the bisectors until they intersect each other.
can you make a clear step by step explanation or anything else that will be easy to understan?

we need to assume first that this triangle has sides AB, AC and BC

Step-by-step explanation:

1. to construct the bisector of the line AB

put your protractor point on point A and open it to a desired width then cut an arc in front of the line AB and behind the line somewhere where C is, put back the point of the protractor at point B and then strike the first arc that was created in-front of line AB and then around C, now join the two arcs with a straight line

2. to construct the bisector of line BC

put your protractor on point B and cut an arc in font of line BC and somewhere around A put back the protractor at point C and cut the first arcs that was made, now join the two arcs together with a straight line

3. finally to construct the bisector of line AC

put your protractor point at A and cut an arc in front of line AC and somewhere around B then put the protractor back at point C and cut the first arcs made then joint the two arcs with a straight line.

by the time you do the above you will discover that the three line used to join the arcs will intersect each other somewhere in the middle of the triangle

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a