He physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. the distribution of the number of daily requests is bell-shaped and has a mean of 59 and a standard deviation of 7. using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 52 and 59?

34%

Step-by-step explanation:

Given : The distribution of the number of daily requests is bell-shaped and has a mean of 59 and a standard deviation of 7.

i.e. and

According to the 68-95-99.7 rule, about 68% of the population lies in one standard deviation from the mean.

About 34% of the population lies one standard deviation above the mean and About 34% of the population lies one standard deviation below the mean.

For the given situation, 34% of lightbulb replacement requests lies one standard deviation below the mean .

i.e.About 34% of lightbulb replacement requests lies between and .

i.e. About 34% of lightbulb replacement requests lies between and .

i.e. About 34% of lightbulb replacement requests lies between and .

Hence, the approximate percentage of lightbulb replacement requests numbering between 52 and 59 = 34%

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

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the answer is 11.2 (i know i’m late)