Let x be the number of packages being mailed by a randomly selected customer at a certian shipping facility. suppose the distribution is x is as followsx | 1 2 3 4p(x) | .4 .3 .2 .1(a) consider a random sample of size n=2 (two customers), and let xbar be the sample mean number of packagesshipped. obtain the probability distribution of xbar.(b) use (a) to calculate p (xbar < = 2.) if a random sample of size 4 is selected, what is p (xbar < = 1.5)? (hint: don't list all possible outcomes; onlythose for which xbar < = 1.) find v(xbar)

the correct answer is 1: 2

step-by-step explanation:

hope this your welcome : )

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.