You invested $19,000 in two accounts paying 5% and 9% annual interest, respectively. if the total interest earned for the year was
$1390, how much was invested at each rate?

0.08x + 0.09y = 1700,     where x is the amount that has 8% interest

                                               y is the amount that has 9% interest

                              equation (1)

x+y = 19000

x = 19000 - y ,         equation   (2)

substitute (2) into (1):

0.08(19000 - y) + 0.09y = 1700

1520-0.08y+0.09y = 1700

so, y = 18000

x = 19000-y=1000

(1000,   18000) is the answer    

Just to let you know I’m in 7th grade

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9