A6000-seat theater has tickets for sale at $28 and $40. how many tickets should be sold at each price for a sellout show to generate a total revenue 194400
the number of tickets for sale at $28 should be
the number of tickets for sale at $40 should be

3,833 for $28

2167 for $40

Step-by-step explanation:

Let X be the number of tickets sold at the price of $24, And Y be the number of tickets sold at the price of $40.

Now,   $ 28X will be the revenue generated due to the $28 tickets

And,   $40Y will be the revenue generated due to the 40$ tickets.

Now, Total revenue generated should be $194400.

Thus ,   28X + 40Y  = 194400  -(1).

Also,

Total number of seats in theater is 6000.

So, X + Y = 6000.  -(2)

X = 6000 - Y.

Put in equation 1

We get ,    168,000 - 28Y + 40Y = 194,400

                   12Y = 26,000

                      Y = 2,166.66

Since , Y is of 40 $ so minimum tickets sold should be 2167.

X = 3,833.

javeir earned 56 dollors more than kyle so kyle and javier had 14w but javier made 56 dollors more so 14w plus 56 equals 70w so kyle has 14w

step-by-step explanation: hope i plz give me brainliest with the points so this is not constant cause it says last week so its clearly not every week