You work for a robotics company that is making a new line of hamburger-making robots to be sold to fast-food chains. this is a big-ticket item, so sales will be slow at first, but should pick up over time. your marketing department estimates that the sales growth rate will increase linearly by 2 robots per month per month. in the first month (t 0), for which you have already booked sales for 10 units, the growth rate is expected to be 5 robots per month. how many total robots do you expect to sell by the end of the tenth month (t = 9)?

565 robots

Step-by-step explanation:

We can do this numerically, month by month:

At t = 0, sale is 10 units. Growth rate is 5 robots per month.

At t = 1, sale is 15 units. Growth rate is 7 robots per month.

At t = 2, sale is 22 units. Growth rate is 9 robots per month.

At t = 3, sale is 31 units. Growth rate is 11 robots per month.

At t = 4, sale is 42 units. Growth rate is 13 robots per month.

At t = 5, sale is 55 units. Growth rate is 15 robots per month.

At t = 6, sale is 70 units. Growth rate is 17 robots per month.

At t = 7, sale is 87 units. Growth rate is 19 robots per month.

At t = 8, sale is 106 units. Growth rate is 21 robots per month.

At t = 9, sale is 127 units. Growth rate is 23 robots per month.

So the total robots we can expect to sell by the end of tenth month is

565 robots.

the answers are in the images, i received 100% on this assignment. hope this !

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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