Aboat a moving with speed 8kmh leaves point p whose position vector is r1=4i+3j heading directly towards point q whose position vector is r2=2i+5j. at the same time another boat b leaves point 0i+0j. if the velocity of boat b is vector vba=root2(-5i+3j), find a. the veloctiy of boat b b. the timetaken when the boats are close c. the shortest distance apart

$9.41

step-by-step explanation:

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2