Elsa is taking physical fitness tests in her strength training class. each day, her results are compared to her results from previous days. the first day she completes a test is considered the baseline and is represented by 0. for instance, on the first day she did the flexibility test, her result was calculated as 0. on the second day, in comparison to her first day's result, she was able to reach 1/16inches less than the first day, which was recorded as - 1/16. then, on the third day, elsa recorded a result of -5/8.

a. on which day did elsa reach farther: the second or third day?

b. by how much?

me d:

A) The second day

B) 9/16 inches

Step-by-step explanation:

A) Elsa reached farther on the second day because -1/16 > -5/8

B) To calculate this we must first put both fractions above the same denominator. We can then subtract the smaller one from the bigger one:

-1/16 - (-10/16) = 9/16

Elsa reached 9/16 inches farther on the second day then she did on the first.

the value of x is 9 ⇒ answer b

step-by-step explanation:

* we can solve this problem using cosine and sine rule

- in δ abc

∵ ab = 36 , bc = 28 , ac = 16

- lets find the measure of angle b using the cosine rule

∵ cos b = [ab² + bc² - ac²]/2(ab)(bc)

∴ cos b = [36² + 28² - 16²]/2(36)(28)

∴ cos b = 19/21

∴ m∠b = cos^-1(19/21) ≅ 25°

- lets find the measure of angle a using the sine rule

∵ sina/bc = sinb/ac = sinc/ab

∴ sina/28 = sin25°/16 ⇒ by using cross multiplication

∴ sina = 28 × sin25°/16

∴ sina = 0.7396

∴ m∠a = sin^-1(0.7396) ≅ 48°

- from the figure m∠abd = m∠dbc

∵ m∠abc = 25°

∴ m∠abd = 25°/2 = 12.5°

- in δabd

∵ m∠a = 48° , m∠abd = 12.5°

∵ the sum of the measures of the interior angles of any δ is 180°

∴ m∠adb = 180° - (48° + 12.5°) = 119.5°

∵ ab = 36

∵ ad = x

- use the sine rule to find x

∵ sin∠adb/ab = sin∠abd/x

∴ sin119.5°/36 = sin12.5°/x ⇒ by using cross multiplication

∴ x = 36 × sin12.5°/sin119.5° = 8.95 ≅ 9

* the value of x is 9

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