The probability of a successful optical alignment in the assembly of an optical data storage product is p = 0.6. assume the trials are independent. round your answers to four decimal places (e. g. 98.7654). (a) what is the probability that the 1st successful alignment requires exactly 4 trials? (b) what is the probability that the 1st successful alignment requires at most 4 trials? (c) what is the probability that the 1st successful alignment requires at least 4 trials?

a)

b)

c)

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

Part a

For this case we want this probability

Part b

For this case we want this probability:

If we find the individual probabilities we got:

And replacing we have:

Part c

For this case at least 4 trials means that the random variable X needs to be 4 or more

And we found already the probabilities P(X=1),P(X=2) and P(X=3) so we just need to replace:

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

3

step-by-step explanation: