50 point for this question:
find values of a and b that make the following equality into identity:

1) The values of 'a' and 'b' are and respectively.

2) The values of 'a' and 'b' are '3' and '-3' respectively.

Step-by-step explanation:

1) Given:

We solve this by partial fraction method.

Taking LCM in the RHS we get,

To find the value of 'a', substitute x = 2. This would make 'b' vanish leaving an equation with 'a'.

Now, Substitute to solve for 'b'.

Therefore, a = and b =

2) Given

We follow the same procedure as (1).

Taking LCM we get

Substituting x = 2, we get:

3 = a(-1)

Also, Substituting x = 3, we get:

3 = b(1)

Therefore, the values of a and b are -1 and 1 respectively.

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?