Mathematics, 03.12.2019 19:31 bevanscory123

The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y - 1 = 1(x - 12). what is the
standard form of the equation for this line?
x – 4y = 8
© x - 4y = 2
4x - y = 8
4x - y = 2

Answers: 3

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The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y - 1 = 1(x - 12). what is the standard form of the equation for this line? x – 4y = 8 © x - 4y = 2 4x - y = 8 4x - y = 2

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Another question on Mathematics

The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y - 1 = 1(x - 12). what is the
standard form of the equation for this line?
x – 4y = 8
© x - 4y = 2
4x - y = 8
4x - y = 2