Use the identity below to complete the tasks a^3-b^3=(a-b)(a^2+ab+b^2) when using the identity for the difference of two cubes to factor 64x^6-27

see explanation

Step-by-step explanation:

Given that the the difference of  cubes is

a³ - b³ = (a - b)(a² + ab + b²)

Given

64 - 27 ← a difference of cubes

with a = 4x² and b = 3, thus

= (4x²)³ - 3³

= (4x² - 3)(16 + 12x² + 9) ← in factored form

5/6

step-by-step explanation:

if i remember correctly with perpendicular stuff you just take away the negative

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation: