Recall the equation for a circle with center ( h , k ) and radius r . at what point in the first quadrant does the line with equation y = x + 1 intersect the circle with radius 6 and center (0, 1)?

  (3√2, 1+3√2) ≈ (4.243, 5.243)

Step-by-step explanation:

The line has a slope of 1 and goes through the center of the circle, so will intersect the circle at the point ...

  (6, 6)/√2 +(0, 1) = (3√2, 1+3√2) ≈ (4.243, 5.243)

-18 degrees is the answer : )

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64