Mathematics, 03.12.2019 06:31 cmob13

Suppose that the insurance companies did do a survey. they randomly surveyed 400 drivers and found that 320 claimed they always buckle up. we are interested in the population proportion of drivers who claim they always buckle up. construct a 95% confidence interval for the population proportion who claim they always buckle up. what is the error bound?

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Answer from: jannaleigh

The 95% confidence interval would be given (0.761;0.839). The error bound is $Me=\pm 0.0392$

Step-by-step explanation:

1) Data given and notation

n=400 represent the random sample taken

X=320 represent the people drivers claimed they always buckle up

$\hat p=\frac{320}{400}=0.8$ estimated proportion of people drivers claimed they always buckle up

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Confidence =95% or 0.95

p= population proportion of people drivers claimed they always buckle up

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

2) Calculating the interval for the proportion

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.8 - 1.96 \sqrt{\frac{0.8(1-0.8)}{400}}=0.761$

$0.8 + 1.96 \sqrt{\frac{0.8(1-0.8)}{400}}=0.839$

And the 95% confidence interval would be given (0.761;0.839). The error bound is $Me=\pm 0.0392$

We are confident that about 76.1% to 83.9% of people drivers that they always buckle up at 95% of confidence

Answer from: Quest

step-by-step explanation:

Answer from: Quest

amount of oatypop that contains the prize = 40%

amount of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

= s +f s +f f s+ff f s+ff f f s+ infinity.where f= failure,s= success

= or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

= = 87.04 %

step-by-step explanation:

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