Iwon't pass this class

what is the slope of a line that contains
the point (-0.5, 4) and has a y-intercept
of -5?

The slope of line that contain the points ( - 0.5 , 4 ) and has y- intercept of - 5 is -18

Step-by-step explanation:

Given as :

The points that satisfy the line is ( - 0.5 , 4 )

The y - intercept = - 5

The equation of line is

y = m x + c

Where m is the slope of line

∵ For y- intercept , c = - 5

Now, points on the line is ( - 0.5 , 4 ) and y  intercept c = - 5 is

y = m x + c

or,  4 = m × ( - 0. 5 ) + ( - 5 )

Or, 4 = - 0. 5 m - 5

or, 4 + 5 = - 0.5 m

Or, 9 = - 0. 5 m

∴ m =

So, Slope = m = - 18

Hence the slope of line that contain the points ( - 0.5 , 4 ) and has y- intercept of - 5 is -18   Answer

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~