When x=3 and y=5 by how much does the value of 3x^2-2y exceed the value of 2x^2-3/

x = 3

y = 5

3x^2 – 2y

= 3(3)^2 - 2(5)

=> 3(9) - 10 = 17

And 2x^2– 3y

=> 2(3)^2 - 3(5)

=> 2(9) - 15 = 3

17 - 3 = 14

This gives 3x^2 – 2y exceeding 2x^2– 3y by 17 - 3 = 14

sorry, i can't understand your question. will later if you describe more clearly!

: )

i got 86 for this

hope this !

if you need an explanation just ask