Anna is an avid reader. her generous grandparents gave her money for her birthday, and she decided to spend at most $150.00 on books. reading spot is running a special: all paperback books are $8.00 and hardback books are $12.00. anna wants to purchase at least 12 books.

1.) write a system of inequalities to reach po represent the situation.

2.) graph the region of the solutions to the inequality.

3.) name two different solutions for anna's situation.

1) equations 1, 2, 3  and 4

2)  see picture attached (the region of the solutions is in yellow)

3) x = 18.75 and y =0

   y = 12.5 and x =0

Step-by-step explanation:

Let's call x the number of paperback books bought and y the number of  hardback books bought.

She decided to spend at most $150.00. All paperback books are $8.00 and all hardback books are $12.00. Combining this information we get:

x*8 + y*12 ≤ 150 (eq.  1)

Anna wants to purchase at least 12 books. Mathematically:

x + y ≥ 12 (eq. 2)

On the other hand,  both the number of paperback books bought and the number of  hardback books bought must be positive, that is:

x ≥ 0 (eq. 3)

y ≥ 0 (eq. 4)

3) One possible solution is got if we make y = 0 and to take eq. 1 as an equality, then:

From eq. 1: x*8 = 150

x = 150/8 = 18.75

equations 2 and 3 are also satisfied

Another option is to make x = 0 and to take eq. 1 as an equality, then:

From eq. 1: y*12 = 150

y = 150/12 = 12.5

equations 2 and 4 are also satisfied

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40