Arectangular box is 10 in. wide, 10 in tall, and 7 in. long. what is the diameter of the sm
the diameter is 10 in.
(round to the nearest tenth of an inch as needed.)

on your paper it doesn't say the answer but the the answer is altitude

step-by-step explanation:

this answer is !

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

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