Kiaria is 7 years alder tham jay . martha is twice as old as kiaria , the sum of their three ares is 7u , find the ratio of jay, s age to kiatias age to marhas age

The ratio  of Jay's age to Kiaria's age to Martha's age is 1: 2 : 4.

Step-by-step explanation:

Here, let us assume the age of jay = u years

So, the age of Kiaria = Age of Jay + 7   =   u + 7

And, the age of Martha  = 2 x ( age of Kiaria) = 2 ( u + 7)

Now, the sum of the ages  = 7 u

⇒ (u) + (u + 7)  + 2 ( u + 7)  = 7 u

or,  u + u + 7 + 2 u + 14 = 7 u

or, 4 u +  21 =  7 u

⇒ 3  u = 21  or u = 21/3 =  7

⇒ u  = 7 years

Hence, the age of Jay =  m = 7 years

Age of Kiaria = m + 7 = 7 + 7 = 14 years

Age of Martha  =2 (  m+7) = 2 ( 7 +7) = 28 years

So, the ratio of Jay's age to Kiaria's age to Martha's age

is 7: 14: 28 = 1: 2 : 4

Hence, the final ratio of the ages is 1: 2 : 4.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

54.864 meters

step-by-step explanation: