Reflecting adef across the vertical line x=-2, we get its image ad'ef'.
suppose dd', ee', and ff intersect the line of reflection at j, k, and l as shown below.

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answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

answer: can you give the

step-by-step explanation: