Divide the following polynomials
(2x2+x+3)/ (x-2)

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of

0

.

2

x

-

3

2

x

2

-

3

x

+

5

Divide the highest order term in the dividend

2

x

2

by the highest order term in divisor

2

x

.

x

2

x

-

3

2

x

2

-

3

x

+

5

Multiply the new quotient term by the divisor.

x

2

x

-

3

2

x

2

-

3

x

+

5

+

2

x

2

-

3

x

The expression needs to be subtracted from the dividend, so change all the signs in

2

x

2

−

3

x

x

2

x

-

3

2

x

2

-

3

x

+

5

-

2

x

2

+

3

x

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

x

2

x

-

3

2

x

2

-

3

x

+

5

-

2

x

2

+

3

x

0

Pull the next term from the original dividend down into the current dividend.

x

2

x

-

3

2

x

2

-

3

x

+

5

-

2

x

2

+

3

x

0

+

5

The final answer is the quotient plus the remainder over the divisor.

x

+

5

2

x

−

3

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.