An explosion causes debris to rise vertically with an initial speed of 120 feet per second. the formula h equals negative 16 t squared plus 120 t describes the height of the debris above the ground, h, in feet, t seconds after the explosion. when will the debris be 56 feet above the ground?

The debris will be at a height of 56 ft when time is 0.5 s and 7 s.

Step-by-step explanation:

Given:

Initial speed of debris is,

The height 'h' of the debris above the ground is given as:

As per question, . Therefore,

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

Using quadratic formula to solve for 't', we get:

Therefore, the debris will reach a height of 56 ft twice.

When time during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at , the height is 56 ft.

answer: y = -12x + 108

step-by-step explanation: do (y = m x+b) formula.