what is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (−4, −3)?

y + 3 = −4(x + 4)
y + 3 = –one-fourth(x + 4)
y + 3 = one-fourth(x + 4)
y + 3 = 4(x + 4)

The equation in point-slope form of the line that is perpendicular to the given line and passes through the point (−4, −3) is; y + 3 = 1/4(x + 4)

The slope of the given straight line graph is; -4.

The slope of the perpendicular line is therefore; -1/-4 = 1/4

In essence, the point-slope form of the equation of a straight line takes the form;

I'm this case; a = -3 , b= -4 and m = 1/4

The equation is therefore; y + 3 = 1/4(x + 4)

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its an acute right triangle

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