The number rounded to the hundred place is 42300. what is the least possible sum of the two missing digits? justify your answer.

Least possible sum of missing digits is 3 that is 3 + 0 and missing numbers are 30

Solution:

Given that number 42,__2 rounded to the hundred place is 42300 .

Need to determine least possible sum of the two missing digits.

first lets see what all numbers can be rounded to 300  

number from 251 to 349 can be rounded to 300 as 251 is more close to 300 than 200 and 349 is closer to 300 than 400.  

But in our case at ones place we are having 2 , so possible numbers having 2 at ones place and in between  251 to 349 are 252 , 262 , 272 , 282 , 292 , 302 , 312 , 322 , 332  and 342.

but we are only concern numbers at hundred and tens place

so now we have 25 , 26 , 27 , 28 , 29 , 30 , 31 , 32 , 33 and 34.  

Out of this set we want numbers whose sum is least . So if you carefull observer that number is  30 having least sum as 3 + 0 = 3 .

So missing numbers in 42,__2 is 30 and number is 42,302.

Hence we can conclude that least possible sum of missing digits is 3 that is 3 + 0 and missing numbers are 30.

-1/2 +2

step-by-step explanation:

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm