Mofor's school is selling tickets to the annual dance competition. on the first day of ticket sales the school sold 7 adult tickets and 6 tickets for a total of $143. the school took in $187 on the second day by selling 4 adult tickets and 13 student tickets. find the price of an adult ticket and the price of a student ticket.

the price of an adult ticket is $11

the price of a child ticket is $11

Step-by-step explanation:

Let x represent the price of an adult ticket.

Let y represent the price of a student ticket.

On the first day of ticket sales the school sold 7 adult tickets and 6 student tickets for a total of $143. This means that

7x + 6y = 143 - - - - - - - - - -1

The school took in $187 on the second day by selling 4 adult tickets and 13 student tickets. This means that

4x + 13y = 187 - - - - - - - - - -2

Multiplying equation 1 by 4 and equation 2 by 7, it becomes

28x + 24y = 572

28x + 91y = 1309

Subtracting

-67y = -737

y = -737/-67 = 11

Substituting y = 11 into equation 1, it becomes

7x + 6×11 = 143

7x + 66 = 143

7x = 143 - 66 = 77

x = 77/7 = 11

there is no diagram : /

step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0