How much horsepower would a challenger srt® hellcat redeye widebody need to tow the ss delphine up the industry standard: davis dam grade climb?

pro tips:
davis dam assumed grade = 7% air density is sea level conditions (.002377 slugs/f^t3) w(weight) of the ss delphine + trailer + redeye = 3,922,000 + 150,000 + 4451 lbs crr = coefficient of rolling resistance = .015 assume combined cda is 1555 ft^2 sae j2807 (davis dam grande climb) - min speed is 40mpg (59 ft/s) f(drag) = 1/2p x v^2 x c(d)a f(rolling resistance) = w x cos x crr f(weight) = w x sin f(sum) = f(drag) + f(rr) + f(weight) p = f(sum)xv convert to horsepower = p(1hp/550ft lbf/sec)

37769 hp

Step-by-step explanation:

from the pro tips given w ( weight of the SS Delphine + trailer + Redeye) = 3922000 + 150000 + 4451 Lbs Crr = 4076451 ibf

coefficient of rolling resistance = 0.015

Combined CDA = 1555 ft ^2

to get Ф = tan ⁻¹ ( 0.07 ) = 4.0041 degrees

To get F (w)  you will multiply it with sin Ф

= F ( w ) = 4076451 ibf * sin( 4.0041 ) = 284655.02 Ibf

to calculate F ( rr ) you will multiply it with cos Ф

F( rr) = 4076451 ibf * 0.015 * cos ( 4.0041 ) = 60997.50 ibf

the total sum of F ( force ) will be

F ( rr ) + F ( w)

= 60997.50 + 284655.02 = 352085.82 Ibf

therefore P ( power ) will be

p = 352085.82 ibf * 59 ft/s = 20773063.27 ft*ibf/s

to calculate how much horsepower the challenger will need to tow the SS Delphine will be calculated as below

HP = (20773063.27 ft*ibf/s ) * ( 1 hp / 550 ft*ibf/s ) = 37769.21 = 37769 hp  

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

10.416 m/s

step-by-step explantion:

distance=100m

time= 9.6s

average speed=100/9.6

=10.416 m/s