How much money should be deposited today in an account that earns 7% compounded semiannually so that it will accumulate to $11,000 in three years?
the amount of money that should be deposited is $ n
(round up to the nearest cent.)

$8950.37

Step-by-step explanation:

Use the compound amount formula A = P(1 + r/n)^(nt), in which P is the initial amount of money (the principal), r is the interest rate as a decimal fraction, n is the number of times per year that interest is compounded, and t is the number of years.

Here we have A = $11,000, n = 2, r = 0.07 and t = 3, and so:

$11,000 = P(1 + 0.07/2)^(2*3), or

$11,000 = P (1.035)^6

                                           $11,000        $11,000

Solving for P, we get P = = = $8950.37

                                            1.035^6          1.229

Depositing $8950.37 with terms as follows will result in an accumulation of $11,000 after 3 years.

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3