Consider the linear homogeneous system x'=p11(t)x+p12(t)y, y'=p21(t)x+p22(t)y. x′=p11tx+p12ty, y′=p21tx+p22ty. show that if x = x1(t), y = y1(t) and x = x2(t), y = y2(t) are two solutions of the given system, then x = c1x1(t) + c2x2(t), y = c1y1(t) + c2y2(t) is also a solution for any constants c1 and c2.

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).

he has 140 chickens because he has 10 times more chickens than ducks and he has 14 ducks so 14*10=140

my dear correct answer is option number 3