1. over the past year, a university’s computer system has been struck by a virus at an average rate of 0.4 viruses per week. the university’s information technology managers estimate that each time a virus occurs, it costs the university $1000 to remove the virus and repair the damages it has caused. assuming a poisson distribution, what is the probability that the university will have the good fortune of being virus-free during the upcoming week? during this same week, what is the expected amount of money that the university will have to spend for virus removal and repair?

Step-by-step explanation:

Since 0.4virus occurs per week and it cost the university $1000 to remove one virus.

There next week we expect to 0.4 virus and cost required will be =0.4×$1000. this will amount to $400

$53.50

step-by-step explanation:

you have to subtract the amount of money chuck earned ($72.50) by the cost of the gas for the mower ($11.25) and the new string for the trimmer he bought ($7.75).

72.50-11.25=61.25

and then subtract $61.25 by the second thing he bought (the new string for the trimmer)

61.25-7.75=53.5

so in total it's $53.50 (53 dollars and 50 cents)

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step-by-step explanation: