Agrocer sells milk chocolate at $2.50 per pound, dark chocolate at $4.30 per pound, and dark chocolate with almonds at $5.50 per pound. he wants to make a mixture of 50 pounds of mixed chocolates to sell at $4.54 per pound. the mixture is to contain as many pounds of dark chocolate with almonds as milk chocolate and dark chocolate combined. how many pounds of each type must he use in this mixture?

10 pounds of milk chocolate, 15 pounds of dark chocolate, and 10 + 15 = 25 pounds of almond chocolate

Step-by-step explanation:

Let x be the number of pounds of milk chocolate that he needs to use in the mixture. And y is the number of pounds of of dark chocolate. Since the mixture must use almonds chocolate as much as the other 2 combined in term of weight, and the total weight is 50 pounds. That means

milk_choco_weight + dark_choco_weight + almond_choco_weight = 50

x + y + (x + y) = 50

2(x+y) = 50

x+y = 25 or x = 25 - y

Since we know the price of the mixture, we can use the following equation

2.5milk_choco_weight + 4.3dark_choco_weight + 5.5almond_choco_weight = 4.54total_weight

2.5x + 4.3y + 5.5(x+y) = 50*4.54

2.5x + 4.3y + 5.5*25 = 227

2.5x + 4.3y = 227 - 137.5 = 89.5

We can substitute x = 25 - y

2.5(25 - y) + 4.3y = 89.5

62.5 - 2.5y + 4.3y = 89.5

1.8y = 27

y = 15

so x = 25 - y = 25 - 15 = 10

So we need 10 pounds of milk chocolate, 15 pounds of dark chocolate, and 10 + 15 = 25 pounds of almond chocolate

answer: (x)+4-5=-3

step-by-step explanation:

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: